Calculate the Motor Current where:

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Current:

$I = \dfrac{(P/\mu) \times 1000}{\sqrt{3} \times V_{pp} \times PF} = \dfrac{(90/0.97) \times 1000}{\sqrt{3} \times 400 \times 0.85} =157.555 \enspace Amps$

Apparent Power:

$S = \dfrac{\sqrt{3} \times V_{pp} \times I_{p}}{1000} = \dfrac{\sqrt{3} \times 400 \times 157.555}{1000} =109.157 \enspace kVA$

Reactive Power:

$Q = \sqrt{P^2 - S^2} = \sqrt{90^2 - 109.157^2 } =108.329 \enspace kVAr$

Phase Angle:

$\theta = Cos(PF) \times \dfrac{ 180 }{pi} = Cos(109.157) \times \dfrac{ 180 }{ 3.141592 } = 37.814 \enspace Degrees$