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Calculation No.: Calc-001
Revision: A
Description:
Created By: Engineer Name
Project: Project Name
Project No.: P001
Client: Client Name

Load Flow Analysis - Gauss-Seidel Method

System: 3-bus network, base 100.0 MVA / 11.0 kV Method: Gauss-Seidel (standard) Converged in 10 iterations

Network Diagram

Load Flow Analysis - 3 Bus System Z = 0.020+j0.060 Z = 0.080+j0.240 Z = 0.060+j0.180 Bus 0 Slack |V| = 1.0500 pu ∠ 0.00° Bus 1 PV |V| = 1.0400 pu ∠ 1.42° Bus 2 PQ |V| = 0.9501 pu ∠ -4.15° Bus Types: Slack (Ref) PV (Gen) PQ (Load) Converged in 10 iterations

Bus types and solved voltages

Step 1: Y-bus Admittance Matrix

The bus admittance matrix is assembled from the line impedances (per-unit).

Formula: $$ y_{ij} = \frac{1}{z_{ij}} = \frac{1}{R_{ij} + jX_{ij}} $$
Formula: $$ Y_{ii} = \sum_{k \neq i} y_{ik} + y_{\text{shunt},i} $$
Formula: $$ Y_{ij} = -y_{ij} \quad (i \neq j) $$
Parameter Symbol Value Notes
Self admittance Y_{00} 6.2500 - j18.7500
Mutual admittance Y_{01} -5.0000 + j15.0000
Mutual admittance Y_{02} -1.2500 + j3.7500
Mutual admittance Y_{10} -5.0000 + j15.0000
Self admittance Y_{11} 6.6667 - j20.0000
Mutual admittance Y_{12} -1.6667 + j5.0000
Mutual admittance Y_{20} -1.2500 + j3.7500
Mutual admittance Y_{21} -1.6667 + j5.0000
Self admittance Y_{22} 2.9167 - j8.7500

Step 2: Gauss-Seidel Update Equation

For each non-slack bus i, with S_i = P_i + jQ_i the net injection. Buses j < i use the already-updated V_j^(k+1); buses j > i use V_j^(k).

Formula: $$ V_i^{(k+1)} = \frac{1}{Y_{ii}} \left( \frac{S_i^*}{V_i^{(k)*}} - \sum_{j \neq i} Y_{ij} V_j \right) $$

Step 3: PV Bus Voltage Magnitude Enforcement

PV (generator) buses: 1.

Formula: $$ V_i^{(k+1)} = |V_i|_{\text{spec}} \cdot e^{j \angle V_i^{\text{temp}}} $$

Where Q limits are enforced, a PV bus that hits a limit is held at that limit and treated as a PQ bus.

Formula: $$ Q_i^{(k+1)} = \text{Im}\left\{ V_i^{(k+1)} \left( \sum_j Y_{ij} V_j \right)^* \right\} $$

Step 4: Convergence Check

Tolerance ε = 1.00e-06. Converged in 10 iterations.

Formula: $$ \max_i \left| V_i^{(k+1)} - V_i^{(k)} \right| < \varepsilon $$

Step 5: Final Bus Voltages

Solved bus voltages (magnitude and angle, per-unit on the system base):
Parameter Symbol Value Notes
Bus 0 (Slack) V_{0} 1.0500 ∠ 0.000° 11.550 kV
Bus 1 (PV) V_{1} 1.0400 ∠ 1.424° 11.440 kV
Bus 2 (PQ) V_{2} 0.9501 ∠ -4.146° 10.451 kV

Step 6: Power Injection Verification

Actual injections are recalculated from the solved voltages and checked against the specified values (positive = generation into the bus).

Formula: $$ S_i = V_i \left( \sum_j Y_{ij} V_j \right)^* $$
Parameter Symbol Value Notes
Bus 0 (Slack) real power P_{0} 5.1904 specified 0.0000 MW, mismatch 5.19e+00 MW
Bus 0 (Slack) reactive power Q_{0} 61.1329 specified 0.0000 MVAr
Bus 1 (PV) real power P_{1} 100.0002 specified 100.0000 MW, mismatch 1.75e-04 MW
Bus 1 (PV) reactive power Q_{1} 4.4388 specified 4.4388 MVAr
Bus 2 (PQ) real power P_{2} -100.0000 specified -100.0000 MW, mismatch 8.57e-07 MW
Bus 2 (PQ) reactive power Q_{2} -50.0000 specified -50.0000 MVAr

Step 7: Line Power Flows

Flow leaving bus i towards bus j; the branch loss is the sum of the flows measured at both ends.

Formula: $$ S_{ij} = V_i \, I_{ij}^* , \quad S_{\text{loss},ij} = S_{ij} + S_{ji} $$
Parameter Symbol Value Notes
Line 0 → 1 S_{01} -35.2955 + j29.8275 loss 0.3874 MW + j1.1622 MVAr
Line 0 → 2 S_{02} 40.4859 + j31.3054 loss 1.9005 MW + j5.7015 MVAr
Line 1 → 2 S_{12} 64.3173 + j33.1042 loss 2.9027 MW + j8.7081 MVAr

Step 8: System Summary

Total real power loss: 5.1906 MW Total reactive power loss: 15.5718 MVAr Convergence: Yes (10 iterations)

Standards Reference

IEEE Std 399: Power Systems Analysis (Brown Book) AS/NZS 3000: Electrical installations
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