[[ calculationForm.title || displayName ]] Page [[ pages.length ? activeIndex+1 : 0 ]] of [[ pages.length ]]

[[ dlg.mode === 'copy' ? 'Save a copy' : 'Save calculation' ]]

[[ dlg.error ]]

Your Company
Calculation No.: Calc-001
Revision: A
Description:
Created By: Engineer Name
Project: Project Name
Project No.: P001
Client: Client Name

Input Parameters

The following design parameters were considered for this calculation:
Parameter Symbol Value Notes
Voltage (Single Phase) V 240 V Single-Phase System
Efficiency η 100 At rated load
Power Factor PF 0.85 Lagging

Calculations

All calculations were performed in accordance with IEC standards and good engineering practice.

Current Calculation

The full-load current is calculated using the single-phase formula: This represents the current drawn by the single-phase load.

Formula: $$ \begin{aligned} I_{(A)} &= \frac{\left( \frac{P}{\eta} \right) \times 1000}{V_{(V)} \times PF} \\ &= \frac{\left( \frac{15}{1} \right) \times 1000}{240 \times 0.85} \\ &= 73.5 \; Amps \end{aligned} $$

Phase Angle Calculation

The phase angle is calculated using the formula:

Formula: $$ \begin{aligned} \theta &= \cos^{-1}(PF) \times \frac{180}{\pi} \\ &= \cos^{-1}(0.85) \times \frac{180}{3.142} \\ &= 31.8^\circ \end{aligned} $$

Single-Phase Voltage and Current Phasors

Single-Phase Voltage and Current Phasors V I φ = 31.8°

The phasor diagram shows the single-phase voltage and current phasors with the phase angle (φ) between them. The solid red line represents voltage phasor, while the dashed blue line represents current phasor lagging behind voltage.

Figure 1: Single-phase phasor diagram showing voltage and current relationship

Single-Phase Power Relationships

Single-Phase Power Triangle P = 15.00 kW Q = 9.30 kVAr S = 17.64 kVA θ = 31.8°

The power triangle illustrates the relationship between active power (P), reactive power (Q), and apparent power (S). Active power does useful work, reactive power oscillates between source and load, and apparent power is the vector sum of both.

Figure 2: Power triangle showing P, Q, and S relationships

Summary of Results

Below is the summary of calculated values for ease of reference:
Parameter Symbol Value Notes
Current I 73.5 A Load Current
Apparent Power S 17.6 kVA Load
Active Power P 15 kW Load
Reactive Power Q 9.3 kVAr Load

Approval:

This calculation has been reviewed and approved by:
Created By
Engineer Name
Date: ..........................
Checked
By: .............................
Date: ..........................
Approved
By: .............................
Date: ..........................
Client Approved
By: .............................
Date: ..........................

Scan to View Online

Scan this QR code with your mobile device to view the calculation online.

Scan to access this calculation from any device